Can C struct assignment use brace syntax?

Question

Possible Duplicate:
Struct initialization of the C/C++ programming language?

I'm re-learning C and asking myself if something like this is possible:

typedef struct Link {
    struct Node a;
    struct Node b;
    float weight;
    } Link;

Link links[LINK_NUMBER];
links[0] = {nodes[0], nodes[1], 5};

instead of:

Link link0 = {nodes[0], nodes[1], 5};
links[0] = link;

@Juliano: I found the solution in this topic - see below. Thank you! — xyz-123, Jun 11 '11 at 18:09

score 5 · Accepted Answer · answered Jun 11 '11 at 18:07

5

that's what I was searching for:

links[0] = (Link) {nodes[0], nodes[1], 5};

answered Jun 11 '11 at 18:07

xyz-123

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Note that this is only valid in C99 and GNU C. Many legacy compilers will not understand this syntax. I mentioned this in the original question this one is a duplicate of. – Juliano Jun 11 '11 at 18:19

score 1 · Answer 2 · answered Jun 11 '11 at 17:40

1

Are you asking if structs can be assigned? If so, the answer is yes.

answered Jun 11 '11 at 17:40

the question was actually if it is possible to use the brace syntax in assignments. – xyz-123 Jun 11 '11 at 17:43

score -1 · Answer 3 · answered Jun 11 '11 at 17:40

-1

That doesn't work because a Link can't contain another Link.

However, it can contain a pointer to another Link (a Link*).

Regarding the assignment: You can only use the brace syntax when initializing a value, not when setting a value. (I believe this changes in C++0x/C++11, though.)

answered Jun 11 '11 at 17:40

user541686

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C99 supports structure literals, which can be used in assignments. – David Given Jun 11 '11 at 18:10

Can C struct assignment use brace syntax?

3 Answers3