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I'm trying to play an audio file. In my IDE (intellij) that works completely fine, but when running in a JAR, I get the error java.io.FileNotFoundException: D:\soni801\Documents\Redsea Productions\The Great X Wars\alpha-0.0.7.1.jar\audio\click.au (The system cannot find the path specified)

The file's location inside the JAR is audio/click.au, and the JAR is located at D:\soni801\Documents\Redsea Productions\The Great X Wars\alpha-0.0.7.1.jar which afaik should make the absolute path D:\soni801\Documents\Redsea Productions\The Great X Wars\alpha-0.0.7.1.jar\audio\click.au, however the system can't find a file at this location? What's happening here?

This is the code in my AudioPlayer.java file:

AudioInputStream inputStream = AudioSystem.getAudioInputStream(new File(this.getClass().getProtectionDomain().getCodeSource().getLocation().toURI().getPath() /*+ "/res"*/ + filePath).getAbsoluteFile());

Clip clip = AudioSystem.getClip();
clip.open(inputStream);

Alternatively, you can find the entire file, as well as the rest of the project, on the GitHub repository

All help is appreciated.

I am aware that this might be a duplicate of other questions, but unfortunately other solutions didn't solve my problem

If the question is unclear, comment any improvements I could make, and I will edit the question

Soni
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    See [Reading a resource file from within jar](https://stackoverflow.com/questions/20389255/reading-a-resource-file-from-within-jar) – SDJ Jul 21 '20 at 17:55
  • Now getting `java.lang.ClassCastException: java.io.BufferedInputStream cannot be cast to javax.sound.sampled.AudioInputStream` – Soni Jul 21 '20 at 20:09

1 Answers1

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The AudioSystem.getAudioInputStream method is overloaded and can accept a File, a URL or an InputStream as an argument. Of these, URL is usually the best choice.

It's advantage over File is that a URL can address a file within a jar, which a File cannot do.

It's advantage over InputStream is that additional conditions are imposed: the audio file must support mark and reset methods. My experience with audio files is that it's kind of hit or miss as to whether this will be possible or not. I confess I don't know the specifics as to why.

To obtain a URL from your jar, the simplest form it perhaps the following:

URL url = this.getClass().getResource("yourAudioFileName");

This assumes that the audio resource is in the same package as the class "this". Subfolders of the package can be addressed as well, this way. But I don't think the symbol "../" can be counted on to obtain a resource from a parent folder.

Alternatively, instead of 'this' you can specify a class in the package or parent package of the audio resource. Also, you can prefix the address with a "/". In this last case, e.g., this.getClass().getResource("/yourAudioFileName"), the root source folder of the project is the starting point for the address rather than the package holding 'this'.

Phil Freihofner
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