How to determine the size of dynamically allocated array in C?

Question

I have a structure of which I will need an array. I have to pass that array as an argument and iterate that array. So, How do I determine the size of the array in the function? I know we can pass the size as another argument, but I am trying to avoid passing second argument. Thank you in advance.

Here is the code:

#include<stdio.h>
#include<stdlib.h>

typedef struct {
    int weight;
    int profit;
}Object;

void IterateArray(Object *objects) {
    int size = sizeof(objects) / sizeof(objects[0]);
    printf("Size: %d", size);
    //for (int i = 0; i < size; i++) {
    //}
}

void main() {
    int n = 5;
    //Object objects[n];                // Can't run this
    Object *objects = (Object*)calloc(n, sizeof(Object));
    printf("Size of objects: %d\n", sizeof(objects));
    printf("Size of objects[0]: %d\n", sizeof(objects[0]));
    IterateArray(objects);
}

For the above code I am getting following output.

Size of objects: 4
Size of objects[0]: 8
Size: 0