while executing below code i'm getting NullPointerException

Question

While executing below code i'm getting NullpointerException.

  public class SftpConn
      {
      public List<String> searchableFields(String sheetName, int column) {
              if (sheet == null) {
                  sftpConnect();
              }
              List<String> test=null;
              sheet = wb.getSheet(sheetName);
              int rowcount = sheet.getLastRowNum();
              for (int i = 1; i <= rowcount; i++) {
                  Row r = CellUtil.getRow(i, sheet);
                  key = CellUtil.getCell(r, column).getStringCellValue();
                  System.out.println("key = "+key);
                  test.add(key);
              }
              return test;
          }
      }

2.Below is the main class where i'm calling "searchableFields" from searchableFields

3.every time i'm seeing same error please suggest"

                public class MyTest {
                public static void main(String[] args) {
                    // TODO Auto-generated method stub
                    SftpConn sftp = new SftpConn();
                    List<String> list = sftp.searchableFields("Searchable Fields", 0);
                    System.out.println(list);
                }
            }

Below is my Out put please suggest that what could be the issue.

          Session connected  true

             key = Check Document


             Exception in thread "main" java.lang.NullPointerException
                 at com.brcc.tool.Configuration.SftpConn.searchableFields(SftpConn.java:120)
                 at com.brcc.tool.Configuration.MyTest.main(MyTest.java:10)

 *

Does this answer your question? [What is a NullPointerException, and how do I fix it?](https://stackoverflow.com/questions/218384/what-is-a-nullpointerexception-and-how-do-i-fix-it) (hint: `test` is never initialized.) — Salem, Jul 08 '20 at 18:34

score 0 · Answer 1 · answered Jul 08 '20 at 18:38

0

You have not initliazed the list, replace:

List<String> test=null;

with:

List<String> test=new ArrayList<>();

answered Jul 08 '20 at 18:38

user1708042

1,561
15
20

score 0 · Answer 2 · edited Jul 09 '20 at 02:18

0

Initialize test with an implementation of the List interface.

List <String> test = new ArrayList<>();

edited Jul 09 '20 at 02:18

frianH

6,710
6
17
42

answered Jul 08 '20 at 18:47

while executing below code i'm getting NullPointerException

2 Answers2