python string parsing with regular expression

Question

I can get numeric with this:

>>> import re
>>> re.findall(r'\d+', '!"123%&654()')
['123', '654']

How can I get all the components ?

['!"', '123', '%&', '654', '()']

@mkrieger1 No I didn't, `re.split(r'(\d+)', '!"123%&654()')` did the trick. Thanks — Philippe, Jul 04 '20 at 11:14

score 0 · Accepted Answer · answered Jul 04 '20 at 10:54

0

For reference, with findall, you would greedily look for only digits, or only non-digits:

re.findall(r'\d+|\D+', '!"123%&654()')
# ['!"', '123', '%&', '654', '()']

split is a little cleaner.

answered Jul 04 '20 at 10:54

cs95

1 Answers1