Hava a string like this:
"let key1=value1; let key2=value2;"
I want to select the key and value as groups using regex, I've tried using look around.
/(\w+)(?=\=)(\w+);/g
but it doesn't work with me, any suggestions?
Asked
Active
Viewed 68 times
0
Wiktor Stribiżew
- 561,645
- 34
- 376
- 476
Prince Al-harasis
- 45
- 6
-
Maybe: `let\s(\w+)=(\w+);` where you can get group 1 as keys and group2 as values? – JvdV Jun 27 '20 at 13:10
-
Just consume it, `/(\w+)\s*=\s*(\w+);/g`. However, you should not use regex to parse JS code. There are parsers for it. – Wiktor Stribiżew Jun 27 '20 at 13:10
-
@JvdV nope it will select the equal, also will select the white spaces – Prince Al-harasis Jun 27 '20 at 13:13
-
@WiktorStribiżew it will select the equal which I don't want to, am trying to edit a string code before running it on the virtual machine. – Prince Al-harasis Jun 27 '20 at 13:15
-
1It won't select it. It will match it. But you will be able to get the captured substrings. – Wiktor Stribiżew Jun 27 '20 at 13:18
-
`Array.from("let key1=value1; let key2=value2;".matchAll(/(\w+)\s*=\s*(\w+)/g), x => [x[1], x[2]])` – Wiktor Stribiżew Jun 27 '20 at 13:30
3 Answers
0
The following regex should do the trick: (let (\w+) ?= ?(\w+);?)+.
Each let statement will be a match where the key will be the group 2 and the value the group 3.
Samuel Martineau
- 127
- 1
- 1
- 10
0
The (?=\=) expression part is a lookahead, a zero-width assertion, it does not consume text but requires it to be present on the right. When you say (?=\=)(\w+) you want \w+ pattern to start matching on =. As \w does not match =, your regex always fails.
Use
/(\w+)=(\w+);/g
JavaScript (borrowed from How do you access the matched groups in a JavaScript regular expression?):
var myString = "let key1=value1; let key2=value2;";
var myRegexp = /(\w+)=(\w+);/g;
match = myRegexp.exec(myString);
while (match != null) {
console.log(match[1] + "," + match[2]);
match = myRegexp.exec(myString);
}
Ryszard Czech
- 16,363
- 2
- 17
- 35
