Regex to capture everything except the previous capture

Question

I'm trying to parse some strings where the values could be given like:

stuff "Something" stuff

or

stuff 'something' stuff

I solved this bit easily with:

(?<quote>"|')(?<quoted_value>[^'"]+)\k<quote>

However I've come across a problem where I have:

stuff "Today's Top 10" stuff

And I thought I could use the captured quote as the argument for the quoted_value pattern like so:

(?<quote>"|')(?<quoted_value>[^\k<quote>]+)\k<quote>

But I get

Unrecognized escape sequence \k

How can I use the first quote capture value as a condition to capture everything until that value is found again?

@toto `\k` is `Matches the value of a previously captured named group, specified by name.` — Phill, Jun 15 '20 at 08:01
@Toto OH, LEGEND! Yes it works perfectly. Didn't think of using a sub-pattern. Please add that as an answer so I can accept it. — Phill, Jun 15 '20 at 08:08

score 1 · Accepted Answer · answered Jun 15 '20 at 08:10

1

(?<quote>['"])(?:(?!\k<quote>).)*\k<quote>

answered Jun 15 '20 at 08:10

Toto

1 Answers1