How do I covert this ternary statement to an if else statement? (Java)

Question

Here is the ternary statement that I need help converting into an if/else statement:

char rightColor = necklace.charAt(i + 1 == necklace.length() ? 0 : i + 1);

By the way, the `char` type is obsolete, supplanted by Unicode code point integer numbers. — Basil Bourque, Jun 11 '20 at 19:06
Possible duplicate of https://stackoverflow.com/q/35189762/642706 — Basil Bourque, Jun 11 '20 at 19:08
Does this answer your question? [Do Ternary and If/Else compile to the same thing, why?](https://stackoverflow.com/questions/35189762/do-ternary-and-if-else-compile-to-the-same-thing-why) — LazyCoder, Jun 12 '20 at 05:49

score 2 · Answer 1 · answered Jun 11 '20 at 18:20

2

There are many ways, it depends on your logic, here is one of the solution you can do:

int index;
if (i + 1 == necklace.length()) {
    index = 0;
} else {
    index = i + 1;
}
char rightColor = necklace.charAt(index);

answered Jun 11 '20 at 18:20

YCF_L

score 1 · Accepted Answer · answered Jun 11 '20 at 18:20

The ternary operator is equivalent to asking:

Is i + 1 equal to necklace.length?

If true, then the value 0 (at the left of :) is passed to the charAt() method.
If false, then the value i + 1 is passed.

So a verbose equivalent would be, for example:

char rightColor ;

if ( i + 1 == necklace.length() ) {
    rightColor = necklace.charAt(0) ;
} else {
    rightColor = necklace.charAt(i + 1) ;
}

2 Answers2