What is the meaning of multiply operator '*' in python when used before tuple

Asked Jun 03 '20 at 02:49

Active Jun 03 '20 at 03:10

Viewed 30 times

i was reading a Deep-Learning paper and their github repo and i was having trouble understanding how multiply operator works in two lines of their codes.

 alpha_size = tuple((len(x), *(1,)*(x.dim()-1)))

I guess the second one means multiply but what does the first one do as it is ahead of a tuple.

alpha = alpha_t(*alpha_size).uniform_()

same thing happens here as well. They used a multiply operator before a tuple. Can anyone explain? This is new to me. Thank you.

edited Jun 03 '20 at 03:10

asked Jun 03 '20 at 02:49

VD26

2

You should check out this excellent answer regarding `*` in python https://stackoverflow.com/a/3394898/9683408 – Cory Nezin Jun 03 '20 at 02:53
pass tuple as params. – Yang HG Jun 03 '20 at 02:58
1

Please add all textual information as formatted text. Screenshots of code are not acceptable on Stack Overflow. – Klaus D. Jun 03 '20 at 02:59
Yeah I got it, thank you guys – VD26 Jun 03 '20 at 03:16

What is the meaning of multiply operator '*' in python when used before tuple

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