Compare two strings by order in alphabet in java

Question

I have two Strings:

String string1 = "Abcdef"
String string2 = "Axyz"

I usually code in python, so I'm really new to java. How do I compare these to strings and find out which one would come first in a dictionary(I mean the book not the datastructure)?

String have a method that is literaly called `compareTo(String)` with the description `Compares two strings lexicographically.`. I'm sorry but this question shows no research effort at all. — OH GOD SPIDERS, May 19 '20 at 09:17
[Comparing strings by their alphabetical order](https://stackoverflow.com/questions/6203411/comparing-strings-by-their-alphabetical-order) — Robby Cornelissen, May 19 '20 at 09:18
It is more complicated, because lexicographical ordering doesn't necessarily equal alphabetical ordering. — Robby Cornelissen, May 19 '20 at 09:26

score 1 · Accepted Answer · answered May 19 '20 at 09:17

1

Since String implements Comparable you can use compareTo to compare chronologically:

string1.compareTo(string2)

answered May 19 '20 at 09:17

Aniket Sahrawat

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Compare two strings by order in alphabet in java

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