Getting "Undefined" value for Variable even though i have defined variable

Question

HI I have defined variable called "const VA" but in output it is coming undefine cause of that i am not able to see values inside it below is my code.

function createAddress(streetA, cityA, zipcodeA) {
  return
  {
    streetA, cityA, zipcodeA;
  }
}
const VA = createAddress("405", "newyork", "123456");
console.log(VA);

Output is undefined

You can't have a linebreak after a return statement, just one of those things. Move your curly bracket onto the same line (ie `return {` ) — Brian Patterson, May 10 '20 at 16:12
@BrianPatterson, you should probably have that as an answer. — Dane Brouwer, May 10 '20 at 16:12
@JohnLord Once you reach 2000 reputation, you can edit any post and approve or reject suggestions... — FZs, May 10 '20 at 16:59
@BrianPatterson Thanks ,It worked .I am new to JS so these small small issues iam facing thanks for help — Amit Mane, May 11 '20 at 07:45

score 2 · Answer 1 · answered May 10 '20 at 16:15

2

You cannot have a line break for the brackets after the return. Use this instead:

return {
    value,
    value2,
    value3
}

answered May 10 '20 at 16:15

little_monkey

343
3
14

score 1 · Accepted Answer · answered May 10 '20 at 16:14

Due to automatic semi-colon insertion, if you put a line-break after a return statement, javascript will put a semi-colon after it and nothing will be returned. You simply need to move the curly bracket up onto the same line to prevent this.

Reference: ASI

function createAddress(streetA,cityA,zipcodeA)
      {
          return {
                streetA,
                cityA,
                zipcodeA  
             };
      };


const VA = createAddress ('405','newyork','123456');    
console.log(VA);

Getting "Undefined" value for Variable even though i have defined variable

2 Answers2