how to display ajax loading image

Question

I want to show ajax loading image. but don't know how to do that. here is my working ajax script. please help me to integrate ajax loading gif.thanks

$(function() { 
    $( "#slider" ).slider({ 
       stop: function(event, ui) {
              $.ajax({
              url: "ajax.php",
              cache: false,
              async: false,
             data: "",
                  success: function(html){
                $("#result_list").html(html);
              }
            });

         }
    });
});

You should consider making your request asynchronous. – alex May 26 '11 at 05:38 — alex, May 26 '11 at 05:38

MajesticRa · Accepted Answer · 2012-03-17T11:48:43.363

6

$(function() { 
$( "#slider" ).slider({ 
   stop: function(event, ui) {
          $("#place_of_loading_image").show();
          $.ajax({
          url: "ajax.php",
          cache: false,
          async: false,
          data: "",
          success: function(html){ //got the data

            $("#place_of_loading_image").hide(); // hide ajax loader         
            $("#result_list").html(html);        // show downloaded content
          }
        });

     }
    });
});

Where #place_of_loading_image is some container (like div), in a place you would like loader.gif to appear.

<div id="place_of_loading_image" style="display:none"><img src="load.gif"/></div>

edited Mar 17 '12 at 11:48

answered May 26 '11 at 05:39

MajesticRa

13,032
11
58
74

this script is working fine in firefox. but not in opera,chrome, ie. please help me thanks – no_freedom May 27 '11 at 09:02
I edited the post. With this variant you can first remove 'style="display:none"' and see that this image is correctly displayed for all browsers. – MajesticRa May 27 '11 at 09:22

score 2 · Answer 2 · answered May 26 '11 at 05:38

Have you looked at blockui? http://jquery.malsup.com/block/

$(function() { 
    $( "#slider" ).slider({ 
       stop: function(event, ui) {
          $.blockUI({ message: null });  //loading
              $.ajax({
              url: "ajax.php",
              cache: false,
              async: false,
             data: "",
                  success: function(html){
                  $.unblockUI(); //loading complete
                $("#result_list").html(html);
              }
            });

         }
    });
});

score 1 · Answer 3 · answered May 26 '11 at 05:44

Ajax have api ajax start and ajax stop, when ever an ajax request is send this apis triggers

 $(document).bind("ajaxStart.mine", function() {
      $("#image").html("<img src="loading.gif"/>");
    });

$(document).bind("ajaxStop.mine", function() {
  $("#image").html("");
});

Show and Hide your image using classes.

score 0 · Answer 4 · answered May 26 '11 at 05:37

0

Before you start your XHR, show the loading image.

On the success callback of your XHR, hide the loading image.

answered May 26 '11 at 05:37

alex

460,746
196
858
974

Naveed · Answer 5 · 2011-05-26T05:44:51.260

Something like this will help.

At start of your function:

jQuery('#processing').html( '<img src="/images/ajaxBigFlower.gif">' );
$('#submit').attr("disabled", true);

In success part of your function:

jQuery('#processing').html( '' );
$('#submit').attr("disabled", false);

Note: <div id='processing'></div> should be in your HTML and you can set the position of this DIV anywhere on page using css. And set id='submit' for these submit buttons that you want to set as disabled when it is processing...

how to display ajax loading image

5 Answers5

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