How to run loop through table with diff rows ? for example this is input ([[0,4],[2,4],[-1,3]] and output i want is this [[0,1.5],[2,1.5],[1.5,3]]

Question

// It is just changing values of first row and not the whole table ? can someone tell me how to run loop in whole table

def remove_outliers(table):
     mx = max(map(max, table))
     mn = min(map(min, table))
     avg = (mx + mn) / 2
     for row in table:
         row[:] = [avg if x in (mx, mn) else x for x in row]
         return table

Is it answers your question https://stackoverflow.com/questions/16548668/iterating-over-a-2-dimensional-python-list? — OxQ, Apr 05 '20 at 09:25

score 0 · Answer 1 · answered Apr 05 '20 at 09:18

I think your return table is intended wrong. It will return after the first row is processed. Try this:

def remove_outliers(table):
    mx = max(map(max, table))
    mn = min(map(min, table))
    avg = (mx + mn) / 2
    for row in table:
        row[:] = [avg if x in (mx, mn) else x for x in row]
    return table

score 0 · Answer 2 · answered Apr 05 '20 at 09:21

0

The return statement is in the wrong place. The function will exit in the first iteration itself. Un-indent return statement out of for loop. Then it will exit after the complete iteration

for row in table:
    row[:] = [avg if x in (mx, mn) else x for x in row]
return table

answered Apr 05 '20 at 09:21

Aroo

57
1
10

yup it works . My IDE was showing return statement at that place only – Apr 05 '20 at 09:32
Awesome. But why are returning the table again instead of avg or something?? – Aroo Apr 05 '20 at 09:41

How to run loop through table with diff rows ? for example this is input ([[0,4],[2,4],[-1,3]] and output i want is this [[0,1.5],[2,1.5],[1.5,3]]

2 Answers2