How to check if any of array values' lengths is equal to 1

Question

I want to check if any length of value in array is equal to 1. I have an array

SLR = [4, 4000, 4010]

I want to check if any of these values' length: is equal to 1. In this case it's true because there's 4.

I tried to do this that way but of course it failed:

SLR = [4, 4000, 4010]

if(any(len(SLR)) == 1):
        print("True")
    else:
        print("False")

It looks like SLR contains integers, so instead of `len()` maybe something like `any(n < 10 for n in SLR)` — Mark, Mar 04 '20 at 22:42
Numbers don't have lengths; string representations of a number (in a given base) do. — chepner, Mar 04 '20 at 23:15

Pedro Lobito · Accepted Answer · 2020-03-05T00:00:56.170

5

You can cast the int to str and check len(), i.e.:

SLR = [4, 4000, 4010]
if [x for x in SLR if len(str(x)) == 1]:
    print("yes")

Or taking advantage of short-circuiting as @kaya3 suggested:

if any(len(str(x)) == 1 for x in SLR):
    print("yes")

To use with negative numbers:

SLR = [-9, 22, 4000, 4010]
if any(-10 < n < 10 for n in SLR):
    print("yes")

edited Mar 05 '20 at 00:00

answered Mar 04 '20 at 22:45

Pedro Lobito

2

`any(len(str(x)) == 1 for x in SLR)` has the advantage of short-circuiting, and not building an unnecessary list. – kaya3 Mar 04 '20 at 22:47
1

A beautiful way of doing it, @kaya3. Thank you – Dautomne_ Mar 04 '20 at 22:48

score 0 · Answer 2 · answered Mar 05 '20 at 00:12

0

As an alternative to the other answers, you could filter the list and return a length greater than 1 for the final subset:

return len(list(filter(lambda x: len(str(x)) == 1, SLR))) >= 1

answered Mar 05 '20 at 00:12

c4llmeco4ch

2 Answers2