how to insert %20 in place of space in android

Question

I have a xml URL file in which there are white spaces i want to replace white spaces with %20.. how to do this????

SAXParserFactory spf = SAXParserFactory.newInstance();
SAXParser sp = spf.newSAXParser();
XMLReader xr = sp.getXMLReader();

/** Send URL to parse XML Tags */
URL sourceUrl = new URL(
                "http://www.arteonline.mobi/iphone/output.php?gallery=MALBA%20-%20MUSEO%20DE%20ARTE%20LATINOAMERICANO%20DE%20BUENOS%20AIRES");

XMLHandlerartistspace myXMLHandler = new XMLHandlerartistspace();
xr.setContentHandler(myXMLHandler);
xr.parse(new InputSource(sourceUrl.openStream()));

`URLEncoder.encode(value, "UTF-8")` is the solution. – Paresh Mayani Oct 19 '12 at 12:11 — Paresh Mayani, Oct 19 '12 at 12:11

score 55 · Accepted Answer · edited Jan 10 '13 at 04:58

55

Try this:

String temp = http://www.arteonline.mobi/iphone/output.php?gallery=MALBA%20-%20MUSEO%20DE%20ARTE%20LATINOAMERICANO%20DE%20BUENOS%20AIRES

temp = temp.replaceAll(" ", "%20");
URL sourceUrl = new URL(temp);

edited Jan 10 '13 at 04:58

HighLife

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answered May 18 '11 at 13:26

Sumant

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I think this is the wrong approach. The URL (excluding the host part) should be URL-encoded (using `URLEncoder.encode`). After doing that, you can replace the `+` characters with `%20`. If you don't use `URLEncoder.encode`, then there's the risk that other special characters in the URL might cause problems. (Note that `+` to represent a space character is perfectly valid in a URL; you might not even need `%20`.) – Ted Hopp Aug 19 '13 at 21:33
+1 Thank you for solution. It worked like a charm! You saved my day man ;) Thank you so much again ;) – Simon Dorociak Sep 01 '14 at 20:25
Do note that URI.Builder solution below is correct. This gets the job done.. but in a professional setting you want the solution from SudoCode – StarWind0 Mar 01 '16 at 03:58

sudocode · Answer 2 · 2011-05-18T13:32:28.087

35

When you build your URL you should use URLEncoder to encode the parameters.

StringBuilder query = new StringBuilder();
query.append("gallery=");
query.append(URLEncoder.encode(value, "UTF-8"));

If you already have the whole URL in a String or a java.net.URL, you could grab the query part and rebuild while URLEncoding each parameter value.

edited May 18 '11 at 13:32

answered May 18 '11 at 13:25

sudocode

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This is the right way. If you are using a regex yourself or replaceAll then you are doing it wrong. – Robert Massaioli May 18 '11 at 13:28
But be sure that you dont URL encode the host part of the url and the '/' characters inside the url. try a substring of the complete url or do it in the build process as sudocode suggested with a string builder. – DArkO May 18 '11 at 13:30
7

If for some reason OP can't live with `+` representing spaces and really needs `%20`, it's easy enough to call `replace("+", "%20")` after calling `URLEncoder.encode`. – Ted Hopp Aug 19 '13 at 21:34
why `query.append("gallery=");` ? – Muhammed Refaat Dec 05 '18 at 19:48
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@MuhammedRefaat the parameter name and equals sign do not need to be URL encoded. The parameter value should be. – sudocode Dec 10 '18 at 16:53

score 21 · Answer 3 · edited Feb 11 '20 at 20:03

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Just one addition to sudocode's response:

Use android.net.Uri.encode instead of URLEncoder.encode to avoid the "spaces getting converted into +" problem. Then you get rid of the String.replaceAll() and it's more elegant :)

StringBuilder query = new StringBuilder();
query.append("gallery=");
query.append(android.net.Uri.encode(value));

edited Feb 11 '20 at 20:03

Ellen Spertus

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answered Oct 18 '13 at 08:44

voghDev

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Correct usage is android.net.Uri.encode(value,":/"), Where second argument is list of characters which shouldn't be encoded – Softec Feb 28 '15 at 08:52
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This should be the most up-voted and selected one. +1 – Ankit Aggarwal Dec 06 '16 at 13:02
@Softec I removed the optional second argument per your comment. – Ellen Spertus Feb 11 '20 at 20:04

score 4 · Answer 4 · edited May 23 '17 at 12:34

4

I guess you want to replace all spaces, not only white.

the simplest way is to use

"url_with_spaces".replaceAll(" ", "%20);

However you should consider also other characters in the url. See Recommended method for escaping HTML in Java

edited May 23 '17 at 12:34

Community

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answered May 18 '11 at 13:28

bart

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what if you want to encode the blue, or the red spaces in the url? – Christopher Perry Aug 09 '13 at 22:15

score 3 · Answer 5 · answered May 01 '19 at 03:56

3

For anyone that needs space characters to be encoded as a %20 value instead of a + value, use:

String encodedString = URLEncoder.encode(originalString,"UTF-8").replaceAll("\\+", "%20")

answered May 01 '19 at 03:56

TheIT

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djg · Answer 6 · 2013-12-04T20:20:00.877

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String s = "my string";
s=s.replaceAll(" ", "%20");

edited Dec 04 '13 at 20:20

answered May 18 '11 at 13:25

djg

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score 1 · Answer 7 · edited May 09 '14 at 10:07

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Try using URIUtil.encodePath method from the api org.apache.commons.httpclient.util.URIUtil.

This should do the trick for you.

edited May 09 '14 at 10:07

Tim Kist

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answered Jan 22 '14 at 09:32

Paul John

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how to insert %20 in place of space in android

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