Replace with regular expression repetition

Asked Feb 03 '20 at 15:46

Active Feb 03 '20 at 15:46

Viewed 18 times

I would like use regular expression to replace a pattern by an other :

re.compile(r"<class '(.*)'>").sub("\\1", "<class 'int'>")
>>> 'int'

But how can i manage repetition cases ? Like:

re.compile(r"<class '(.*)'>").sub("\\1", "<class 'int'>, <class 'str'>")
>>> 'int\'>, <class \'str'  # i would like 'int, str'

asked Feb 03 '20 at 15:46

bux

If you want to extract, use `re.findall`, and a lazy dot, `.*?` – Wiktor Stribiżew Feb 03 '20 at 15:48
Hello @WiktorStribiżew, can you provide an example ? I am not familiar with python `re`module. – bux Feb 03 '20 at 15:49
`re.compile(r"").sub("\\1", ", ")` this will work fine as Wiktor has mentioned. – Akash senta Feb 03 '20 at 15:52
This is working like a charm, thanks ! – bux Feb 03 '20 at 15:53
1

If you want to get a list, `['int', 'str']`, use `re.findall(r"", text)` – Wiktor Stribiżew Feb 03 '20 at 15:56

0 Answers0