I wanted to know how I could separate a text in the different letters it has without saving the same letter twice in python. So the output of a text like "hello" will be {'h','e',l','o'}, counting the letter l only once.
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Andrej Kesely
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MIGUEL GP
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5`set(list("hello"))` ? – Nir Alfasi Jan 23 '20 at 22:42
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3Or even set(‘hello’) – Ethan Jan 23 '20 at 22:44
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I like to just do `letters = [l for l in txt]` Then converting it into a set, and back into a list. `lis = list (set (letters))` – OakenDuck Jan 23 '20 at 22:45
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1Does this answer your question? [List of all unique characters in a string?](https://stackoverflow.com/questions/13902805/list-of-all-unique-characters-in-a-string) – AMC Jan 24 '20 at 01:46
2 Answers
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As the comments say, put your word in a set to remove duplicates:
>>> set("hello")
set(['h', 'e', 'l', 'o'])
Iterate through it (sets don't have order, so don't count on that):
>>> h = set("hello")
>>> for c in h:
... print(c)
...
h
e
l
o
Test if a character is in it:
>>> 'e' in h
True
>>> 'x' in h
False
Ben
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There's a few ways to do this...
word = set('hello')
Or the following...
letters = []
for letter in "hello":
if letter not in letters:
letters.append(letter)
hill_sprints
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