how to display the print message from the function imported from another file when called from inside an if block

Question

I create a python function in a file and filename is ifunc.py

def func():
    print('print something')

I have my main program in another file like this:

import ifunc

inputFlag = input('input something:')

if inputFlag == 1:
    ifunc.func()

and this produce nothing, but when I try to import the function outside the if statement like:

import ifunc
ifunc.func()

the print message print something will show up.

Please give me some advice. Thanks in advance!

Cannot reproduce your issue. If you have created a minimal example of your problem, pleases add some additional detail that reflects your actual problem. And please verify that the simplified example you have posted *does indeed* cause the issue you describe — sshashank124, Jan 14 '20 at 04:54
@sshashank124 sorry for the misleading example, I found the problem is actually caused by the `input()` function, I have edited my post. — weeshin, Jan 14 '20 at 05:04

score 1 · Accepted Answer · answered Jan 14 '20 at 05:02

1

You should change the below statement in main code:

The input you are taking is as a string. And if statement checks value of inputFlag to be 1 which is int and not string.

inputFlag = int(input('input something:'))

answered Jan 14 '20 at 05:02

Vaibhav Jadhav

this works! Thank you so much : ） – weeshin Jan 14 '20 at 05:13
@XinWang Can you mark the solution as answer... ;-) – Vaibhav Jadhav Jan 14 '20 at 05:42

1 Answers1