Python3 Sorted function not behaving as expected, getting different output

Question

Why is this weird behaviour:

a  = ['This','is','some','banana']
"_".join(sorted(a)).

Output -

This_is_banana_some

It should give the output -

is_banana_some_this

Am I missing something?

Why would `T` be between `i` and `t`? `T` is 84 and `i` is 105, so `This` should be before `is` — Dharman, Jan 07 '20 at 14:31

score 0 · Accepted Answer · answered Jan 07 '20 at 14:35

0

You need to specify the sorting key - lowercase str in your case.

"_".join(sorted(a, key=str.lower))

This works. By default python places uppercase first.

answered Jan 07 '20 at 14:35

Adarsh Chavakula

1 Answers1