List, dictionary, and tuple values

Question

a=[{"a":30},{"c":("a","=","c")}]

I need values of "c".

for x in a[1].values():
    for j in x:
        print(j, end=" ")

This is my solution but if you have any other short solution for this then tell me.

What's wrong with `a[1]['c']` or even `print(*(_ for _ in a[1]['c']))`? — accdias, Jan 02 '20 at 17:55
What is the question? You're providing an example but does it do what you expect? If yes, why do you need another solution? If not, what do you expect? If I take your actual question literally, the answer is: `"c"`. That's "the value of `"c"`". — pasbi, Jan 02 '20 at 18:17
For those like me who didn't know what the * was, look for "tuple unpacking", or other uses at https://stackoverflow.com/questions/2921847/what-does-the-star-operator-mean-in-a-function-call — B. Go, Jan 02 '20 at 18:21

score 2 · Answer 1 · answered Jan 02 '20 at 17:57

2

You could simply say

for element in a[1]['c']:
       print(element,end=" ")

answered Jan 02 '20 at 17:57

Swetank Poddar

score 2 · Answer 2 · answered Jan 02 '20 at 18:03

2

>>> print(' '.join(*a[1].values()))
a = c

answered Jan 02 '20 at 18:03

Dishin H Goyani

score 2 · Answer 3 · answered Jan 02 '20 at 18:14

2

If you just need the values to be printed, you can unpack the tuple as arguments to print:

print(*a[1]['c'])

answered Jan 02 '20 at 18:14

blhsing

score 1 · Answer 4 · answered Jan 02 '20 at 17:59

1

The same result can be achieved with a comprehension:

>>> a=[{"a":30},{"c":("a","=","c")}]
>>> print(*(_ for _ in a[1]['c']))
a = c
>>>

answered Jan 02 '20 at 17:59

accdias

4 Answers4