Issue with NSString and concatenation

Question

Why this code gives me the following errors?

"use of undeclared identifier baseURL"

and

"Unexpected Interface name NSString, expected expression"

here is the entire block of code

switch (type) {
    case 1:
        NSString *baseURL = [NSString stringWithString:@"http://www.myserver.net/somephp/"];
        NSString *finalURL = [baseURL stringByAppendingString:@"?i="];
        break;
    case 2:
        NSString *finalURL = [baseURL stringByAppendingString:@"?n="];
        break;
    default:
        break;
}

That code works perfectly. Are you creating an other instances with the same variable name? Can you post any other code relative to this error? — max_, May 08 '11 at 19:28

score 2 · Accepted Answer · edited May 23 '17 at 10:34

Sounds like those lines are within a switch statement. If this is the case, move the declaration of the strings outside the switch statement.

NSString *baseURL;
NSString *finalURL;
switch (<expression>) {
    case <constant>:
        baseURL = [NSString stringWithString:@"http://www.myserver.net/somephp"];
        finalURL = [baseURL stringByAppendingString:@"?i="];
        break;
    default:
        break;
}

More information and other techniques to work around this on this question.

Issue with NSString and concatenation

1 Answers1