Need a regular expression which accepts 4 numbers and 1 character exactly in the same format

Question

I need a regular expression which accepts following format 1111A or 1234B.

I used /([0-9]{0,4})&([A-Z])/ but not able to get it.

Remove `&` and probably enclose with `^` and `$`. `^[0-9]{0,4}[A-Z]$` might suffice. Please add some valid/invalid input. — Wiktor Stribiżew, Dec 10 '19 at 11:52
No, `^[0-9]{0,4}[A-Z]$` does not. 4 or 0-4? If only 4, use `^[0-9]{4}[A-Z]$` — Wiktor Stribiżew, Dec 10 '19 at 11:55
`^[0-9]{4}[A-Z]$` should work in JS, ``^[0-9]{4}[A-Z]\Z`` for Python, ``^[0-9]{4}[A-Z]\z`` for PCRE/.NET/Java — Wiktor Stribiżew, Dec 10 '19 at 11:59
4 any numbers or 4 sequential numbers or 4 repeated numbers? — Simon, Dec 10 '19 at 11:59

score 0 · Answer 1 · answered Dec 10 '19 at 12:04

0

Try using ^\d{4}[A-Z]$

const re = RegExp(/^\d{4}[A-Z]$/);
console.log(re.test('1111A'));
console.log(re.test('1A111'));
console.log(re.test('1111AA'));

answered Dec 10 '19 at 12:04

Nitheesh

1 Answers1