Most compact/Pythonic way to check if variable is a positive integer, possible variable types being any variable type including boolean

Question

I am trying to figure out the most compact and pythonic way of checking if a variable is a positive integer. This is what I've tried so far.

a = None
b = 3.4
c = -1
d = 10
e = -5.7
f = '7'
g = [9]
h = {7}
i = 3j
j = r'8'
k = True
l = False

varlist = [a, b, c, d, e, f, g, h, i, j , k, l]

for vv in varlist:
    print( isinstance(vv, int) )

Current Output

False
False
True
True
False
False
False
False
False
False
True
True

Ideal Output

False
False
False
True
False
False
False
False
False
False
False
False

Possible duplicate of [Check if input is positive integer](https://stackoverflow.com/questions/26198131/check-if-input-is-positive-integer) — Sayse, Nov 17 '19 at 19:44
Typo in question or ideal output? You have `c` as True and `d` as False, currently? — David Buck, Nov 17 '19 at 19:46
The answers in that post can convert a float to an int. What I am looking for is to tell me that float is an invalid input — SantoshGupta7, Nov 17 '19 at 19:46
@Sayse the solution works for all cases except for case `k = True' — SantoshGupta7, Nov 17 '19 at 19:49
`isinstance(vv, int) and not isinstance(vv, bool) and vv >= 0` — David Buck, Nov 17 '19 at 19:50

score 2 · Accepted Answer · answered Nov 17 '19 at 19:51

2

If you want exclusively int objects and no subtypes:

type(vv) is int and vv > 0:
    do_stuff()

answered Nov 17 '19 at 19:51

juanpa.arrivillaga

77,035
9
115
152

score 1 · Answer 2 · answered Nov 17 '19 at 19:56

1

for vv in varlist:
    print( type(vv) == type(0) and vv > 0 )

answered Nov 17 '19 at 19:56

Maxxik CZ

313
2
8

`type(vv) == type(0)` right idea, but use `is` to compare types, which are language guaranteed singletons, and `int` is a built-in – juanpa.arrivillaga Nov 17 '19 at 19:58

Most compact/Pythonic way to check if variable is a positive integer, possible variable types being any variable type including boolean

2 Answers2