Python Reversing List Using Slicing

Question

I am trying to create a function that reverses and mutates a list via slicing/appending without using [::-1] or .reverse(). I am looking for any additional resources online but it seems to be the only two popular reserving techniques.
Can anyone help me think of how I can write this?

Use `for` loop to iterate over index backward and append the elements — Sociopath, Nov 14 '19 at 05:46
I'm trying to think of how I would do this with a list of unspecified length — skepticalforever, Nov 14 '19 at 05:46
apart from [::-1] and .reverse() there is another built in function called reversed() — Prathik Kini, Nov 14 '19 at 05:48

score 0 · Answer 1 · answered Nov 14 '19 at 05:50

0

This is one way you can do it:

a = [1, 2, 3, 4]
b = [0]*len(a)

for i in range(len(a)):
    b[len(a) - 1 - i] = a[i]
print(b)

answered Nov 14 '19 at 05:50

learner

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score 0 · Accepted Answer · answered Nov 14 '19 at 06:00

0

I would try:

n = len(a)
for i in range(n):
    a.append(a[n - (i+1)])
a = a[n:]

answered Nov 14 '19 at 06:00

NG_

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Python Reversing List Using Slicing

2 Answers2