extract version number from string by using shell script

Question

I need to extract version number from the following strings .

pattern looks like this.

by using shell script

VAR1=1.1-g13ab57737123
Output 1.1

VAR1=1.2-g328891ahqq12
Output 1.2

VAR1=2.3-g123900a12328
Output 2.3


VAR2=abcd960_1.1-g13ab57737123
Output 1.1

Does this answer your question? [Extract substring using regexp in plain bash](https://stackoverflow.com/questions/13373249/extract-substring-using-regexp-in-plain-bash) — Chris Maes, Nov 13 '19 at 07:59

lenik · Answer 1 · 2019-11-13T08:30:48.760

0

This works:

$ VAR1=1.1-g13ab57737123
$ echo $VAR1
1.1-g13ab57737123
$ echo $VAR1 | grep -o "[0-9]\.[0-9]"
1.1

Or if you need longer numbers:

$ VAR1=1.1234-g13ab57737123
$ echo $VAR1 | grep -o "[0-9]\+\.[0-9]\+"
1.1234

edited Nov 13 '19 at 08:30

answered Nov 13 '19 at 08:23

lenik

1 Answers1