I use cout statements in my program for debugging purposes. I would like to make a function that works like it, or works like printf, but is sensitive to a global variable. If this global variable is true, then it will print to screen. If it is false, then it won't print anything. Is there already a function like this? If not, then how can it be made?
-
possible duplicate of [Macro to turn off printf statements](http://stackoverflow.com/questions/5765175/macro-to-turn-off-printf-statements) – karlphillip May 03 '11 at 22:53
3 Answers
Something like this:
int myPrintf(const char* format, ...)
{
if (globalCheck == 0)
return 0
va_list vl;
va_start(vl, format);
auto ret = vprintf(format, vl);
va_end(vl);
return ret;
}
va_start and va_end take the arguments in the ... and encapsulate them in a va_list. with this va_list you can then the vprintf which is a variant of printf designed exactly for this need.
Side note - usually it is bad practice to use global variables. A better thing to do is to encapsulate it in a class like this -
class ConditionalPrinter {
public:
ConditionalPrinter() : m_enable(true) {}
void setOut(bool enable) { m_enable = enable; }
int myPrintf(const char* format, ...);
private:
bool m_enable;
}
and then to check m_enable instead of the global variable. Usage of this looks like this:
ConditionalPrinter p;
p.myPrintf("hello %d", 1); // printed
p.setOut(false);
p.myPrintf("hello2 %d", 1); // not printed
....
- 73,722
- 51
- 204
- 318
Don't write it yourself. Doing it right is much harder then you think. Even harder when you need threads and efficiency. Use one of existing logging libraries like:
- glog: http://code.google.com/p/google-glog/ (I prefer this - it is lightweight and do what it needs to do)
- Log4cpp http://log4cpp.sourceforge.net/ (powerful and configuration compatible with popular java logging)
- ... add your favorite to this wiki
- 833
- 5
- 12
As someone else said, there are several good logging frameworks available. However, if you want to roll your own, the first thing to note is that cout isn't a function, it's a stream. The function is operator<<. What you can do is something like the following:
/* trace.h */
extern ostream debug;
void trace_init();
void trace_done();
/* trace.cpp */
#include "trace.h"
ostream debug(cout.rdbuf());
static ofstream null;
void trace_init()
{
null.open("/dev/null");
if(output_is_disabled) { // put whatever your condition is here
debug.rdbuf(null.rdbuf());
}
}
void trace_done()
{
null.close();
}
You might have to adjust a bit if you're on a platform without /dev/null. What this does is let you write
debug << "here's some output << endl;
and if you have the output enabled, it will write to cout. If not, it will write to /dev/null where you won't see anything.
For that matter, you could just set cout's rdbuf to somewhere where you won't see that output, but I would find that to be a really bad idea. Creating new streams gives you a lot more flexibility in controlling your output.
- 3,772
- 20
- 18