Cartesian product of a word in python

Question

I am looking for a way to get a cartesian product of a string in the following form,

text = 'school'

I want the result like this,

list_ = [(s,c),(c,h),(h,o),(o,o),(o,l)]

this is what I tried,

text = 'school'
list_=[]
for i in range(len(text)):
  while i < len(text)+1:
    print(text[i], text[i+1])
    list_.append((text[i], text[i+1]))
    i = i+1

I got the necessary list, yet throwing off some errors. Is there any elegant way to do this?

https://docs.python.org/2/library/itertools.html#itertools.product — gstukelj, Oct 23 '19 at 10:55

score 3 · Accepted Answer · answered Oct 23 '19 at 10:53

3

text = 'school'
list(zip(text, text[1:]))

Out[1]:
[('s', 'c'), ('c', 'h'), ('h', 'o'), ('o', 'o'), ('o', 'l')]

answered Oct 23 '19 at 10:53

Alex

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Cartesian product of a word in python

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