how this code works i didn't undestand clearly?

Asked Oct 03 '19 at 10:44

Active Oct 03 '19 at 13:07

Viewed 37 times

const show1 = function(x, y = () => {x = 2; return x;}) {
    console.log(y());
    console.log(x);
};

how does this code work?

what does this thing do ? function(x, y = () => {x = 2; return x;}) {

its just for improve coding knowledge and nothing else :)

asked Oct 03 '19 at 10:44

Selva Ganapathi

1

If `y` isn't passed or is undefined, it sets it to a function that reassigns and returns the first parameter passed – CertainPerformance Oct 03 '19 at 10:46
1

its just default parameter value – ibtsam Oct 03 '19 at 10:48
can you show the linkdude – Selva Ganapathi Oct 03 '19 at 10:48
Actually, that's not quite right, the default parameter's scope is pretty strange, see https://stackoverflow.com/questions/58219009/if-re-declaration-with-var-will-have-effect-on-existed-variable – CertainPerformance Oct 03 '19 at 13:08

0 Answers0