creating sequence in a list in R

Question

Im interested in generating a list with a sequencing of numbers like in this fashion:

list(1:3, 4:6, 7:9)

I have tried variations of using list and seq without luck and using repetition like rep(list(1:3), 3) gets me the right format but without the advancing sequencing so I'm at a loss to what probably is a really simple problem. Thanks in advance.

This isn't clear. What is wrong with `list(1:3, 4:6, 7:9)`? Presumably there is a more general problem you are trying to solve, but if so what is it? — John Coleman, Sep 14 '19 at 16:01
Sorry I should have added im trying to create a list from a long sequence of numbers, for arguments sake 1:300. so 1:3 in list[1], 4:6 in List[2] etc — Krl74, Sep 14 '19 at 16:06
The provided question is sufficient to achieve your goal. But I leave the following for you. `x — jazzurro, Sep 14 '19 at 16:19

score 1 · Answer 1 · answered Sep 14 '19 at 16:24

1

We can use gl to create a grouping variable for splitting the vector

split(x, as.integer(gl(length(x), 3, length(x))))

data

x <- 1:9

answered Sep 14 '19 at 16:24

akrun

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creating sequence in a list in R

1 Answers1

data