4

I am trying to understand what is this java class definition.

abstract public class A<P extends B<?, ?>,Input,Output>
{
...
// class defined
...
}

A c++ programmer moving to java

MeBigFatGuy
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Kazoom
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5 Answers5

3

This defines an abstract class called A, with three type parameters:

  • P, which must be of type B (with any type arguments) or any type derived from it
  • Input, of any type
  • Output, of any type

Of interest is the first type parameter. In C++, for a type-based template parameter, you can supply any type; in Java, you have the option to constrain the type by what class and/or interfaces such a type must also extend/implement.

Chris Jester-Young
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1

A bit of "translation":

"abstract" means this class may have abstract (~=pure virtual) methods.

class A is a generic (~template) definition

P extends ... is an extra constraint on generic parameter, should be subclass of ...

P extends B<?, ?> means that the generic parameter#1 is a subclass of another generic class

Sasha O
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    It might not have pure virtuals. Abstract classes in Java only have the property of not being directly instantiatable in and of themselves. – Joseph Ottinger Apr 26 '11 at 03:10
1

It's an abstract class definition (obviously) with 3 generic parameters.

The first parameter P has a constraint that it has to be of type (or that extends) class/interface B which has two generic parameters (no constraint on those) so it could be like 

public class B<T1, T2> {

}

The second and third parameters namely Input and Output have no constraints.

Bala R
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-1

The angle bracket notation is for Java Generics.

Jim Ferrans
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  • -1 You'd think that C++ people already know what generics are, surely? C++ templates are much beefier than Java generics. – Chris Jester-Young Apr 26 '11 at 03:09
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    the main difference being in c++ each specialization creates a separate class, whereas in java the specialization is lost at compile time. – MeBigFatGuy Apr 26 '11 at 03:11
  • @MeBigFatGuy: well... *after* compilation phase is complete... Java generics just aren't reified like C++ generics are. – Joseph Ottinger Apr 26 '11 at 03:12
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    @Chris: Generics != C++ templates, and it's not clear the OP had run across the term before. – Jim Ferrans Apr 26 '11 at 03:14
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    +1 to @Jim: Java Generics and C++ templates share only superficial similarity. They use a similar syntax and Java generics approach a subset of the problems approached by C++ templates, but their implementation and are quite different! – Joachim Sauer Apr 26 '11 at 07:13
-1

Well, to really understand it you'd want to include more of the definition, but B is a class with generics itself, and A has three generic references in it; it's a bit pathological, but it's fairly easy to step through.

Joseph Ottinger
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