I have a list of integer lists. I am trying to convert it to a list of integers.
int_list = [[0], [1], [2], [3], [4], [5], [6]]
new_list = []
for i in int_list:
new_list.append(i)
print(new_list)
Wanted output:
[0, 1, 2, 3, 4, 5, 6]
My output:
[[0], [1], [2], [3], [4], [5], [6]]
A very pythonic way of doing this would be to use list comprehension:
int_list = [[0], [1], [2], [3], [4], [5], [6]]
new_list = [value for sub_list in int_list for value in sub_list]
print(new_list)
An explaination of this can be found here: https://spapas.github.io/2016/04/27/python-nested-list-comprehensions/
There are many more ways that some people would prefer, for example a programmer who uses functional programming may prefer:
from operator import add
from functools import reduce
int_list = [[0], [1], [2], [3], [4], [5], [6]]
print(reduce(add, int_list))
If you want a more verbose and easier to understand version, you could use:
int_list = [[0], [1], [2], [3], [4], [5], [6]]
new_list = []
for i in int_list:
new_list.extend(i)
print(new_list)
You almost had it:
int_list = [[0], [1], [2], [3], [4], [5], [6]]
new_list = []
for i in int_list:
new_list.append(i[0])
print(new_list)
Output:
[0, 1, 2, 3, 4, 5, 6]
int_list = [[0], [1], [2], [3], [4], [5], [6]]
new_list = []
for i in int_list:
new_list += i
print(new_list)
1) you can use itemgetter with map
from operator import itemgetter
new_list = list(map(itemgetter(0), int_list))
print(new_list)
output:
[0, 1, 2, 3, 4, 5, 6]
2) or you can use chain from itertools
from itertools import chain
new_list = list(chain(*int_list))
print(new_list)
output:
[0, 1, 2, 3, 4, 5, 6]
