How to pick only Capital characters from the string?

Question

I am try to pick capital characters from the string with the help of a function and for loop but i can't figure out how i can do it i try using toUpperCase as you see it in the code but it is not work any idea how i can do it ?

function onlyCapitalLetters(cap){
    var string = "";
    for(var i = 0; i < cap.length; i++){
        if(cap[i] === cap.toUpperCase()){
            string += cap[i];
        }
    }
    return string;
}

onlyCapitalLetters("Apple");

check the ascii value of it for the range of capital letters. — venkata krishnan, Jul 22 '19 at 12:32
You just need to change `cap[i] === cap.toUpperCase()` to `cap[i] === cap[i].toUpperCase()` — Cuong Le Ngoc, Jul 22 '19 at 12:33
May be a duplicate of - https://stackoverflow.com/questions/6055152/finding-uppercase-characters-within-a-string — Monika Mangal, Jul 22 '19 at 12:33
Have you considered using a simple regex?`"Only Capital Letters".match(/[A-Z]/g) // ["O", "C", "L"]` — Christian C. Salvadó, Jul 22 '19 at 12:35
`cap[i] === cap.toUpperCase()` -- this is one cause for not working. It compares one character to the uppercase version of the entire string. Change it to compare the character with the uppercase version of the same character. — axiac, Jul 22 '19 at 12:36
anyone mind telling me simple way rather than advanced regex thing ? — Fahad Mir, Jul 22 '19 at 12:40

score 4 · Answer 1 · edited Jul 22 '19 at 12:52

4

You can try the regex, with String.prototype.match to return capital letters only:

function onlyCapitalLetters(cap){
    return  cap.match(/[A-Z]/g, "").join(''); // join the array to return a string
}

console.log(onlyCapitalLetters("Apple"));
console.log(onlyCapitalLetters("BUTTerfly"));
console.log(onlyCapitalLetters("LION"));

edited Jul 22 '19 at 12:52

Alessio Cantarella

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answered Jul 22 '19 at 12:35

Shubh

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4

But its the solution right?? ,one of the possible solution may be easy .It doesn't deserves downvote even if it ddeosn't deserves upvote @axiac – Shubh Jul 22 '19 at 12:39
Kindly comment after down vote a answer. it helpful for the user. – Velusamy Venkatraman Jul 22 '19 at 12:39
I didn't vote this answer (neither up or down). But it qualifies for a down vote. It is not useful because it does not provide a solution for the question. The function in the question returns a string that contains only uppercase letters. The function suggested by this answer returns a boolean. – axiac Jul 22 '19 at 12:45
1

@axiac previously it was returning array ,now with the edit suggested by Dadboz it returns string now – Shubh Jul 22 '19 at 12:47
@Shubh i also noticed that. as per this @axiac you did not run this code ever. but deside its unqualified. his old core is `console.log(onlyCapitalLetters("LION"));` – Velusamy Venkatraman Jul 22 '19 at 12:50

score 1 · Answer 2 · edited Jul 22 '19 at 12:59

1

Can you try like this

function findUpcase(value){
    input = value
    data = ""
    input.split("").map(res => {
        if(res == res.toUpperCase()){
            data = data+ res
        }
    })
    return data
}

console.log( findUpcase("MyNameIsVelu") );
//'MNIV'

edited Jul 22 '19 at 12:59

Lee Taylor

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answered Jul 22 '19 at 12:38

Velusamy Venkatraman

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Now try. its return string – Velusamy Venkatraman Jul 22 '19 at 12:51
Better to use a string throughout instead of joining your array at the end. – Lee Taylor Jul 22 '19 at 12:52

score 0 · Answer 3 · answered Jul 22 '19 at 12:57

0

As noted in comments you need to change cap.toUpperCase() to cap[i].toUpperCase().

But you can do it with just one replace:

console.log('Apple Orange'.replace(/[^A-Z]/g, ""));

answered Jul 22 '19 at 12:57

trincot

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StepUp · Answer 4 · 2019-07-22T13:06:10.043

0

It is possible to use replace method with Regex to eliminate numbers and letters written in lowercase:

let str = 'T1eeeEeeeSssssssTttttt';
let upperCase = str.replace(/[a-z0-1]/g, '')
console.log(upperCase);

edited Jul 22 '19 at 13:06

answered Jul 22 '19 at 12:58

StepUp

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How to pick only Capital characters from the string?

4 Answers4

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