How can I generate a random number which will not be generated again afterwards?

Question

I'd like to create a program which will generate random numbers between 1 and 30 until all numbers have been generated once. Essentially, I want to generate random numbers which will never be generated again afterwards.

import random
test = random.randint(1, 30)

This is what I have so far, but of course, a number already generated will be generated again.

Ah yes, this is what I need. I couldn't see it on the suggestions. Thanks. — Mrmongoose64, Jul 02 '19 at 13:38

score 0 · Accepted Answer · answered Jul 02 '19 at 13:38

0

This will generate a list of 29 numbers (second argument) from given list (first argument). Note that you will get error if second argument is bigger than size of first argument.

import random
randoms = random.sample(range(1, 30), 29)
print(randoms)

answered Jul 02 '19 at 13:38

Toni Sredanović

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So would this print them all at once? – Mrmongoose64 Jul 02 '19 at 13:40
Yes but you can also iterate them and print them one by one or use them however you need. – Toni Sredanović Jul 02 '19 at 13:41
If I only had 1 number generated, how could I assign it to a variable? – Mrmongoose64 Jul 02 '19 at 13:44
I guess `one_random_number = randoms[0]` would do that. – Toni Sredanović Jul 02 '19 at 13:47
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You know that `30` is not included in `range(1, 30)`? – Matthias Jul 02 '19 at 14:49

score 0 · Answer 2 · answered Jul 02 '19 at 13:45

0

Or if you want repeated numbers:

l = []
while len(set(l)) < 30:
    l.append(random.randint(1, 30))
print('\n'.join(map(str, l)))

answered Jul 02 '19 at 13:45

U12-Forward

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How can I generate a random number which will not be generated again afterwards?

2 Answers2