How to run a python script at a specific time(s)

Question

I'd like to write a simple python script for doing a specific job. I'm getting some time and link information from a web site.

times=
[
('17.04.2011', '06:41:44', 'abc.php?xxx'),
('17.04.2011', '07:21:31', 'abc.php?yyy'),
('17.04.2011', '07:33:04', 'abc.php?zzz'),
('17.04.2011', '07:41:23', 'abc.php?www'),]

What is the best way to click these links at the right time? Do I need to calculate the time interval between the current and the one in list and sleep for a while?

I'm really stuck at this point and open to any ideas which could be useful.

possible duplicate of [Python Timed-Script](http://stackoverflow.com/questions/5657429/python-timed-script) — Andreas Jung, Apr 15 '11 at 14:01
dupe of http://stackoverflow.com/questions/5657429/python-timed-script/5658088#5658088 — Andreas Jung, Apr 15 '11 at 14:01

score 11 · Accepted Answer · answered Apr 15 '11 at 14:02

11

Take a look at Python's sched module.

answered Apr 15 '11 at 14:02

Mark Dickinson

27,124
9
79
112

score 7 · Answer 2 · answered Oct 08 '16 at 06:00

you can use schedule module and it is easy to use and will satisfy your requirement.

you can try something like this.

import datetime, schedule, request

TIME = [('17.04.2011', '06:41:44', 'abc.php?xxx'),
    ('17.04.2011', '07:21:31', 'abc.php?yyy'),
    ('17.04.2011', '07:33:04', 'abc.php?zzz'),
    ('17.04.2011', '07:41:23', 'abc.php?www')]

def job():
    global TIME
    date = datetime.datetime.now().strftime("%d.%m.%Y %H:%M:%S")
    for i in TIME:
        runTime = i[0] + " " + i[1]
        if i and date == str(runTime):
            request.get(str(i[2]))

schedule.every(0.01).minutes.do(job)

while True:
    schedule.run_pending()
    time.sleep(1)

I have use request module and get method to call those URL. You can write whichever methods suits you.

score 3 · Answer 3 · edited Jul 16 '19 at 00:45

3

This may help: How do I get a Cron like scheduler in Python? It is about cron-like scheduling in Python. And yes, it is based on sleeps.

edited Jul 16 '19 at 00:45

wjandrea

23,210
7
49
68

answered Apr 15 '11 at 14:05

andrew_d

83
5

score 1 · Answer 4 · answered May 11 '15 at 09:33

I finally made and used this.

def sleep_till_future(f_minute):
    """
        The function takes the current time, and calculates for how many seconds should sleep until a user provided minute in the future.
    """
    import time,datetime


    t = datetime.datetime.today()
    future = datetime.datetime(t.year,t.month,t.day,t.hour,f_minute)

    if future.minute <= t.minute:
        print("ERROR! Enter a valid minute in the future.")
    else:
        print "Current time: " + str(t.hour)+":"+str(t.minute)
        print "Sleep until : " + str(future.hour)+":"+str(future.minute)

        seconds_till_future = (future-t).seconds
        time.sleep( seconds_till_future )
        print "I slept for "+str(seconds_till_future)+" seconds!"

How to run a python script at a specific time(s)

4 Answers4

Linked

Related