Consider the following setup:
trait Foo[A]
object Foo extends Priority2
trait Priority0 {
implicit def foo1: Foo[Int] = new Foo[Int] {}
}
trait Priority1 extends Priority0 {
implicit def foo2: Foo[Boolean] = new Foo[Boolean] {}
}
trait Priority2 extends Priority1 {
implicit def foo3: Foo[Double] = new Foo[Double] {}
}
Now, in a REPL (having loaded the above code up), I can do the following:
scala> def implicitlyFoo[A](implicit foo: Foo[A]) = foo
implicitlyFoo: [A](implicit foo: Foo[A])Foo[A]
scala> implicitlyFoo
res1: Foo[Double] = Priority2$$anon$3@79703b86
Is there a way to encode with some typelevel magic that I want to skip over the instances with A =:= Double, but still let type inference figure out what A is?
I do not want to shadow foo3. This is an MVCE: in my real case, foo3 is a def with other implicit arguments (and may play an indirect role in deriving other Foo's).
I've tried =:!= from shapeless but to no avail:
scala> import shapeless._
import shapeless._
scala> def implicitlyFoo2[A](implicit foo: Foo[A], ev: A =:!= Double) = foo
implicitlyFoo2: [A](implicit foo: Foo[A], implicit ev: A =:!= Double)Foo[A]
scala> implicitlyFoo2
<console>:16: error: ambiguous implicit values:
both method neqAmbig1 in package shapeless of type [A]=> A =:!= A
and method neqAmbig2 in package shapeless of type [A]=> A =:!= A
match expected type Double =:!= Double
implicitlyFoo2
^