Calculate Power of Double with Double exponent in C#

Question

I need to calculate x^y where both x and y are Doubles.

I tried using Math.Pow:

  Double result = Math.Pow(24.69, 2/3);

The value of result is 1 where it should be 8.4790 ...

Any idea why?

`2/3` is integer division, which evaluates to `0`. – Jun 26 '19 at 15:21 — , Jun 26 '19 at 15:21
To fix, say `2.0/3.0` instead. – Joe Sewell Jun 26 '19 at 15:23 — Joe Sewell, Jun 26 '19 at 15:23
A single integer in double notation will suffice – Avin Kavish Jun 26 '19 at 15:27 — Avin Kavish, Jun 26 '19 at 15:27

score 3 · Accepted Answer · answered Jun 26 '19 at 15:24

3

For the exponent you are passing in 2 ints which is do integer division. So it is doing:

Math.Pow(24.69, 0)

To fix this use doubles like this:

Double result = Math.Pow(24.69, 2.0/3.0);

answered Jun 26 '19 at 15:24

Tom Dee

1 Answers1