something wrong with if-else statement in my usecase

Question

I tried to check whether a word contain in a string and then perform later functions but it went into the wrong "if".

a = "3,977"

if "割" or "分" in a:
    print("yes")
elif "," in a:
    print(",")
else:
    print("none")

current result:

"yes"

expected result:

","

This isn't an exact match to the suggested dupe, but it's close enough IMO. Both turn on the meaning of `'foo' or 'bar'` when compared against something else. — Chris, Jun 11 '19 at 02:46

score 1 · Accepted Answer · answered Jun 11 '19 at 02:45

1

Change

if "割" or "分" in a:

into

if "割" in a or "分" in a:

answered Jun 11 '19 at 02:45

Ellisein

score 1 · Answer 2 · answered Jun 11 '19 at 02:46

1

Try this:

a = "3,977"

if any(s in a for s in "割分"):
    print("yes")
elif "," in a:
    print(",")
else:
    print("none")

answered Jun 11 '19 at 02:46

2 Answers2