How to get multiple values from a dictionary in a list of dictionaries?

Question

How do I find and print the name and age of 'id' == 52? Is using a for loop the only way?

name_list = [
    {'id': 11, 'name': 'John', 'Age': 22},
    {'id': 52, 'name': 'Mary', 'Age': 25},
    {'id': 9, 'name': 'Carl', 'Age': 55 }
]

`for rec in name_list: if rec['id'] == 52: print(f"Name: {rec['name']} Age: {rec['Age']}")` — tonypdmtr, Jun 09 '19 at 23:06

Rashid 'Lee' Ibrahim · Accepted Answer · 2019-06-09T23:06:41.473

1

What you are looking for is a standard loop through a list.

for i in name_list:
    if i['id'] == 52:
        print(i['name'])
        print(i['Age'])

edited Jun 09 '19 at 23:06

answered Jun 09 '19 at 23:02

@tonypdmtr good catch. I just wasn't paying attention. Answer has been edited. – Rashid 'Lee' Ibrahim Jun 09 '19 at 23:07
PEP8, try this: `if not i['id'] == 52: continue ....` – JohnkaS Jun 09 '19 at 23:21

score 0 · Answer 2 · answered Jun 09 '19 at 23:06

0

The quickest way I can think of is to use a loop in list comprehension form:

In [1]: [x for x in name_list if x['id'] == 52]
Out[1]: [{'id': 52, 'name': 'Mary', 'Age': 25}]

answered Jun 09 '19 at 23:06

Peter Leimbigler

2 Answers2