How to print 02-Jun-2019 in bash

Question

How to print dd-mmm-yyyy in bash (e.g 02-Jun-2019)

today=$(date +%d-%m-%Y -d "yesterday")

which doesn't give the desired result

I expected to get 02-Jun-2019 but output is 02-06-2019

Have a look at `man date`. All you want to know can be found in there. — kvantour, Jun 03 '19 at 20:02

R4444 · Answer 1 · 2019-06-05T20:24:55.007

3

You can do something like:

date -d "yesterday" '+%d-%b-%Y'

Gives you yesterday's date in the format you desire:

02-Jun-2019

If you want it to be May, then you can do:

date -d "yesterday -1 month" '+%d-%b-%Y'

Gives you:

02-May-2019

edited Jun 05 '19 at 20:24

answered Jun 03 '19 at 19:36

R4444

1 Answers1