JSON returning as undefined

Question

Hello I have an ajax request that submits a form and sends and email, if the email is submitted successfully, I encode a PHP array that looks like this,

$success = array("state" => "Email Sent");

I am then checking the state of data in my ajax request to see if state matches "Email Sent" however when I alert(data) i get undefined, what am I doing wrong? Below is my javascript,

$.ajax({
                    url: "<?php echo base_url(); ?>home/callback",
                    data: $("#callback").serialize(),
                    type: "POST",
                    dataType: "JSON",
                    success: function(data){
                        $("#fancybox-content div").html(data);
                        alert(data.state);
                    }
                });

did you `json_encode($success)` before output? – KJYe.Name Apr 12 '11 at 11:33 — KJYe.Name, Apr 12 '11 at 11:33

score 0 · Answer 1 · answered Apr 12 '11 at 11:35

0

Try to get the html value of the 'fancybox-content' div. $('#fancybox-content').html();

answered Apr 12 '11 at 11:35

Ammu

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score 0 · Answer 2 · answered Apr 12 '11 at 11:35

0

If you alert is failing then are you sure your json is valid? Can you paste it into your question. You can validate it here online at JsonLint.

answered Apr 12 '11 at 11:35

redsquare

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score 0 · Answer 3 · answered Apr 12 '11 at 11:36

how do you return the $succes array?
You should echo the array in a way that would preserve it's format and would be understandable to javascript (not print_r or var_dump):

echo json_decode($success);

that will return a json string representing your php array, which js automatically converts into an object.
Hope this helps.

score 0 · Answer 4 · answered Apr 12 '11 at 11:42

0

use

json_decode($success, true);

When TRUE, returned objects will be converted into associative arrays.

answered Apr 12 '11 at 11:42

diEcho

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JSON returning as undefined

4 Answers4

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