RegEx for matching a URL containing one word and excluding another

Question

I have found examples of a Regex that will match if a string does not contain a particular word. But I am looking for something that will match if it contains a word AND not another word. Example:

I'm dealing with URL exclusions based off of RegEx. I would like it to match if the URL contains collections and not products

The Regex I have found to work if it does not contain products is this: ^((?!products).)*$ Works great but any time I add in a check to make sure it has collections in it, it fails every time.

Here is a sample url I would like it not to match:

https://dummysite.com/collections/frontpage/products/myproduct

But if it were:

https://dummysite.com/collections/frontpage/

It should match.

How do I solve this problem?

I won't recommend using RegEx for this simple case. It's slow. Try ES6 `includes()`. — k3llydev, May 21 '19 at 18:19
@k3llydev I agree 100% but unfortunately have no control over that getting used. It only happens once per page load anyways, so not a huge deal. — Xandor, May 21 '19 at 18:36

Code Maniac · Accepted Answer · 2019-05-21T18:19:29.010

You can use positive lookahead

(?!.*products)(?=.*collections)
      |               |___________  Positive lookahead ( For must condition)
      |___________________________  Negative lookahead ( For must not condition)

let urls = ['https://dummysite.com/collections/frontpage/products/myproduct','https://dummysite.com/collections/frontpage/']

urls.forEach(url=>{
  console.log(url, '\nResult --->', /^(?!.*products)(?=.*collections).*$/.test(url))
})

RegEx for matching a URL containing one word and excluding another

1 Answers1