ValueError: invalid literal for int() with base 10: '0.50' (I couldn't understand other posts on this)

Question

I cannot input a decimal as it comes up with this error

I've tried putting "float" function in different places

def Change():
  Money = int(input("How Much Money Do You Want To Change For Cash? - "))
  CoinType = int(input("What Type Of Coin Do You Want To Change Into? (1.00, 0.50, 0.20, 0.10, 0.05, 0.02, 0.01) - "))
  float(CoinType)
  if CoinType == 1:
    print("You Will Get", Money / CoinType,"Coins")
  if CoinType == 0.50:
    print("You Will Get", Money / CoinType,"Coins")

It should come up with "You will get", Money / CoinType, "Coins"

sidenote: do not store currency in floats. use the smallest denomination and ints. (so, 100 instead of 1, and 1 instead of 0.01). Convert at the end if really needed. Because [floats have their problems.](https://docs.python.org/3/tutorial/floatingpoint.html) — Paritosh Singh, May 14 '19 at 13:58

score 1 · Accepted Answer · answered May 14 '19 at 13:56

You are expecting int input whereas you instruct your user to pass a float value in the following line:

CoinType = int(input("What Type Of Coin Do You Want To Change Into? (1.00, 0.50, 0.20, 0.10, 0.05, 0.02, 0.01) - "))

Therefore, changing it to float should fix the problem:

CoinType = float(input("What Type Of Coin Do You Want To Change Into? (1.00, 0.50, 0.20, 0.10, 0.05, 0.02, 0.01) - "))

score 0 · Answer 2 · answered May 14 '19 at 13:55

0

You should use float

CoinType = float(input("What Type Of Coin Do You Want To Change Into? (1.00, 0.50, 0.20, 0.10, 0.05, 0.02, 0.01) - "))

answered May 14 '19 at 13:55

rdas

18,048
6
31
42

score 0 · Answer 3 · answered May 14 '19 at 13:56

0

Use float in place of int. Integers (int) will not accommodate any decimal

answered May 14 '19 at 13:56

Rakmo

1,588
2
17
34

ValueError: invalid literal for int() with base 10: '0.50' (I couldn't understand other posts on this)

3 Answers3