Parsing integer strings in Java

Question

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How to convert a hexadecimal string to long in java?

I know that Java can't handle this:

Integer.parseInt("0x64")

Instead you have to do this:

Integer.parseInt("64", 16)

Is there something built into Java that can automatically parse integer strings for me using the standard prefixes for hex, octal, and lack of prefix for decimal (so that I don't have to strip off the prefix and explicitly set the base)?

Tim Cooper · Answer 1 · 2011-04-08T18:59:09.880

28

You can use Integer.decode:

Integer.decode("0x64");

The decoding rules are as follows:

Prefix  Type
        DecimalNumeral
0x      HexDigits
0X      HexDigits
#       HexDigits
0       OctalDigits

Note: decode is available in Short, Integer, and Long.

edited Apr 08 '11 at 18:59

answered Apr 08 '11 at 18:53

Tim Cooper

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I knew there was something. :) – biziclop Apr 08 '11 at 18:56

score 4 · Answer 2 · answered Apr 08 '11 at 18:55

4

There's Long.decode().

answered Apr 08 '11 at 18:55

Isaac Truett

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Did you read the details?: _is there something built into Java that can automatically parse integer strings_ – mre Apr 08 '11 at 18:56
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@noob Wanna pick nits, eh? Okay. The question said "integer" not "Integer" and Java Longs are integers. – Isaac Truett Apr 08 '11 at 18:58
Once again, did you _read the details_? No reason to get all pissy. – mre Apr 08 '11 at 19:00
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@noob Of course I read it. Calm down. – Isaac Truett Apr 08 '11 at 19:01

Parsing integer strings in Java

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