How to escap "..."

Question

I R imports columns with no colname as ...1 I need to replace this ... with something else

Trying:

str_replace("hi_...","/././.","&")

what is the expected output. Do you need `"[.]{3}", "&")` – akrun May 02 '19 at 14:27 — akrun, May 02 '19 at 14:27

Pushpesh Kumar Rajwanshi · Accepted Answer · 2019-05-02T14:39:10.520

4

Seems like you are trying to replace each dot . with &. You need to escape . as \\. and use str_replace_all. Try this,

library(stringr)  
str_replace_all("hi_...","\\.","&")

Output,

[1] "hi_&&&"

Just in case you want to replace all three dots with & (which I barely think you wanted), use this,

str_replace("hi_...","\\.\\.\\.","&")

OR

str_replace("hi_...","\\.+","&")

Another way to achieve same can be using gsub

gsub("\\.", "&", "hi_...")

edited May 02 '19 at 14:39

answered May 02 '19 at 14:33

do you have the regex for numbers? – Bruno May 02 '19 at 14:47
1

Sure, for numbers you can use `\d+` and in R you need to escape slash so `\\d+` – Pushpesh Kumar Rajwanshi May 02 '19 at 14:48
can I match only if the word starts with a patter like "_NA"? – Bruno May 02 '19 at 14:52
Sure, for matching a word that starts with `_NA` you can write it is `_NA\w*` Can you give more sample data and tell what you would expect out of it? – Pushpesh Kumar Rajwanshi May 02 '19 at 14:53

score 2 · Answer 2 · answered May 02 '19 at 14:39

2

We can use

library(stringr)
str_replace("hi_...", "[.]{3}", "&")

answered May 02 '19 at 14:39

akrun

2 Answers2