Suppose the following code:
a = [1,2,3]
b = list(a)
print(id(b) == id(a))
This yields to:
False
I would have expected both lists to be of the same id after copying. Why doesn't b have the same id as a?
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3`list(a)` creates a copy. These **are not** the same lists. – freakish Apr 28 '19 at 20:42
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2You're copying the entire list, not the reference to it – Nick stands with Ukraine Apr 28 '19 at 20:42
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In Python all objects have different ids. If they are different objects they have different ids. Simple as that. – Iguananaut Apr 28 '19 at 20:46
1 Answers
4
list creates a new copy of the argument. It expects an iterable and consumes all of the iterable's elements into a new list.
If you wanted a an additional reference/name that refers to the same list, simply use assignment without the call to list.
a = [1,2,3]
b = a
print(id(b) == id(a)) # True
iz_
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