How could I remove adjacent duplicate value without using a loop?

Question

Like the given list is l=[4,2,3,4,4,5]

Turn into l=[4,2,3,4,5]

I try to create an empty list to store the value but it is hard to compare if the two elements are equal with no loop

There is no way to do this "without a loop". You need some sort of loop to check all elements adjacent to each other — TerryA, Apr 20 '19 at 05:51
I could fix it using loop but I try to think of whether using map() and reduce() can solve it or not — Harry, Apr 20 '19 at 06:23

MeeT Valani · Answer 1 · 2019-04-20T06:16:42.037

0

to store every element only once is same like a set. you can use following code.

l=[2,3,4,4,5]
l=list(set(l))
l.sort()

it will give your expected output

edited Apr 20 '19 at 06:16

answered Apr 20 '19 at 05:48

MeeT Valani

score 0 · Answer 2 · edited Apr 20 '19 at 06:24

0

You can use a dictionary which only keeps unique values as its key

l=[2,3,4,4,5]

list(dict.fromKeys(l))

edited Apr 20 '19 at 06:24

greg-449

answered Apr 20 '19 at 05:49

Nobi

Would it be made into a key? I just want to check the adjacent values are equal or not – Harry Apr 20 '19 at 06:09
if removing duplicates is the goal then the outer list function converts the keys back to a list, but if you want to specifically check the adjacent values, you will need a loop. You probably want to reframe your topic then. – Nobi Apr 20 '19 at 06:14
Do you have any idea to use map() or reduce() to fix it? – Harry Apr 20 '19 at 06:20

2 Answers2