Case in Switch statement involving array with conditions

Question

I have an array which is to be iterated and depending on the condition execute task

I have done this with if else and trying it out with Switch.And the condition is if (1 && 2) (then execute A) else if (1) (then execute B) else if (2) (then execute c) else if (none) (then execute D)

function showFiletRelateddata(selectedFilter) {
  /*if (selectedFilter.length === 0) {
    console.log("No data");
  } else if (
    selectedFilter.includes("Request") &&
    selectedFilter.includes("Reservation")
  ) {
    console.log("RequestReservation");
  } else if (selectedFilter.includes("Request")) {
    console.log("Request");
  } else if (selectedFilter.includes("Reservation")) {
    console.log("Reservation");
  }*/

  var filt = selectedFilter;
  for (var i = 0; i < filt.length; i++) {
    var supp = filt[i];
    switch (supp) {
      case "Request":
      case "Reservation":
        console.log("RequestReservation");
        break;
      case "Request":
        console.log("Request");
        break;
      case "Reservation":
        console.log("Reservation");
        break;
      default:
        console.log("No data");
    }
  }
}

The if else is working fine however what correction needs to be made for Switch statement

For ref = Javascript switch case with array or strings

please add an example and the wanted result. do you want only a logging? — Nina Scholz, Apr 15 '19 at 09:28
You're better off using the if/else statement if you're using conditions like `include`. `switch` doesn't really handle those gracefully because it's generally outside of its scope. — Andy, Apr 15 '19 at 09:29
Example is the function(showFiletRelateddata) , I have added, and along with console I have to call an api depending on the Case(If else example is working) — Enthu, Apr 15 '19 at 09:30
This cannot be done like that as var supp = filt[i] can only contain one value. — Syed Mehtab Hassan, Apr 15 '19 at 09:31
So the if else code is the correct approach , Switch cannot be used for such condition . But will wait for some more insights, selectedFilter is an array ,thanks — Enthu, Apr 15 '19 at 09:33
Please try trim the switch argument like ```switch(supp.trim()){....``` — Tamim, Apr 15 '19 at 09:52
@Enthu this works like or operator you can concat the array and then achieve your desired output; — Syed Mehtab Hassan, Apr 15 '19 at 09:54
@SyedMehtabHassan A working example pertaining to my scenario would be great if you can help me with, thanks — Enthu, Apr 15 '19 at 09:56

Syed Mehtab Hassan · Accepted Answer · 2019-04-15T10:33:02.670

1

function showFiletRelateddata(selectedFilter) {
  var filt = selectedFilter;
  var supp = ""
  for (var i = 0; i < filt.length; i++) { //loop over length of array
     supp = supp + filt[i]; // concat elements of array
  }
  
    switch (supp) {
      case "RequestReservation": // if case contains one of the condition
      case "ReservationRequest":
        console.log("RequestReservation");
        break;
      case "Request":
        console.log("Request");
        break;
      case "Reservation":
        console.log("Reservation");
        break;
      default:
        console.log("No data");
    }
  
}
var a = ["Reservation", "Request"];
var b = ["Request","Reservation"];
var c = ["Reservation"];
var d = ["Request"];
 showFiletRelateddata(a);
 showFiletRelateddata(b);
 showFiletRelateddata(c);
 showFiletRelateddata(d);

edited Apr 15 '19 at 10:33

answered Apr 15 '19 at 10:02

Syed Mehtab Hassan

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thanks, I have 2 queries 1. var supp you have used so var 2 time while declaring and then again var inside for (please explain) 2. In The if else condition which I had used include so that approach is correct or not – Enthu Apr 15 '19 at 10:29
1.i have be using var supp = "" because if i only declare it inside loop the first time its value will be undefined which will be concat to the string. i have changed that was a mistake – Syed Mehtab Hassan Apr 15 '19 at 10:31
2. it is correct you can also use indexOf instead of include – Syed Mehtab Hassan Apr 15 '19 at 10:32
ok thanks , and for var usage(point 1) please explain , thank you very much this runs like charm, I will accept this answer – Enthu Apr 15 '19 at 10:34
@Enthu if i donot declare var supp outside the loop the it will concate an undefined inside that because first time it is undefined supp = supp + filt[i] = undefined + filt[i]; – Syed Mehtab Hassan Apr 15 '19 at 10:37
I am a bit confused, u have updated and removed var from inside for, that was a typo I guess right :), I was confused due to that – Enthu Apr 15 '19 at 10:38
@Enthu yeah that what i said in the previous comment it was a mistake – Syed Mehtab Hassan Apr 15 '19 at 10:39

Case in Switch statement involving array with conditions

1 Answers1