using defined char in a case of switch

Question

I used a predefined char variable in a case in my switch and got this error case label does not reduce to an integer

char player = 'X';
  switch(.....){
    case player:
.
.
.
.

I need a solution for this.

Answer 1

From the C11 standard:

The expression of each case label shall be an integer constant expression

player is not a "constant expression".

Please note that in C qualifying a variable as const, does not make it a "constant expression" in the sense of the C standard.

A label either need to be an integer literal, or a enum, which in fact is an integer.

Answer 2

What you want is:

char player = 'X';
switch(player){
    case 'X':
    case 'Y':
    case 'Z':

(A char is an encoding and the encoding is an int)