Replace quotations, period, forward slash and all letters using regex

Question

How can I use regex to replace all the characters in a string that are either alphabetic, a forward slash, a period or double quotations?

I am able to do letters:

"abcd123/./"".replace(/([^\x00-\x80]|\w)/g, "someReplacementText"));

Answer 1

Just place all the characters you want into a non-negated character set:

/[a-zA-Z\/\.\"]/g