Convert a list to dictionary without extra curly brackets being added

Question

Say I have a list like this:

alist = [{'key': 'value'}]

And then I convert it to a dictionary like this

adict = dict(alist)

The formatting becomes

{'{''key: 'value}'}

This makes it so I can't access the data from the dictionary. Is there a way to convert the list to a dictionary without there being extra {' '} -- brackets and single quotes

The code you posted does not run without exceptions. It does not produce the output you posted. Please check again. — Markus Unterwaditzer, Mar 23 '19 at 23:41
Possible duplicate of [How do I merge a list of dicts into a single dict?](https://stackoverflow.com/questions/3494906/how-do-i-merge-a-list-of-dicts-into-a-single-dict) — Michael Doubez, Mar 23 '19 at 23:45

Sheldore · Answer 1 · 2019-03-23T23:39:39.090

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You can use the index 0 to avoid the extra { } braces because the dictionary can be accessed as alist[0]. Moreover, you do not need dict additionally because your list content is already a dictionary

adict = alist[0]

Now you get the desired behavior

print (adict)
# {'key': 'value'}

edited Mar 23 '19 at 23:39

answered Mar 23 '19 at 23:37

Sheldore

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@DeveshKumarSingh: It works for me. Anyway, `dict` is not need here because the list contains already a dictionary. Check my edit – Sheldore Mar 23 '19 at 23:41

score 1 · Answer 2 · answered Mar 23 '19 at 23:40

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If you first structure your list by swapping the curly braces, you won't have any issues using this :)

dict([('A', 1), ('B', 2), ('C', 3)])

answered Mar 23 '19 at 23:40

David S

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score 0 · Answer 3 · answered Mar 23 '19 at 23:43

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If your objective is to initialise a dictionary object with a key value pair (or a bunch of key value pairs), why would you use a list first?

You could simple write

adict = {'key': 'value', 'Hello': 'world' }

print(adict)

answered Mar 23 '19 at 23:43

Gro

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Convert a list to dictionary without extra curly brackets being added

3 Answers3